我正在尝试创建一个对象,但作为一个新进程.我正在关注
this guide并想出了这段代码.
import multiprocessing as mp
import time
class My_class(mp.Process):
def run(self):
print self.name, "created"
time.sleep(10)
print self.name, "exiting"
self.x()
def x(self):
print self.name, "X"
if __name__ == '__main__':
print 'main started'
p1=My_class()
p2=My_class()
p1.start()
p2.start()
print 'main exited'
但是在这里我无法将参数传递给对象.我搜索但没有找到.它不像普通的多进程,我们会做类似的事情:
p1 = multiprocessing.Process(target=My_class, args=('p1',10,))
将参数传递给新进程.
但是类实例的多处理是不同的.现在,我正在以下面的方式传递它.
import multiprocessing as mp
import time
class My_class(mp.Process):
my_vars={'name':'', 'num':0}
def run(self):
self.name=My_class.my_vars['name']
self.num=My_class.my_vars['num']
print self.name, "created and waiting for", str(self.num), "seconds"
time.sleep(self.num)
print self.name, "exiting"
self.x()
def x(self):
print self.name, "X"
if __name__ == '__main__':
print 'main started'
p1=My_class()
p2=My_class()
My_class.my_vars['name']='p1'
My_class.my_vars['num']=20
p1.start()
My_class.my_vars['name']='p2'
My_class.my_vars['num']=10
p2.start()
print 'main exited'
哪个工作正常.但我想对于像大型列表或对象这样的复杂参数可能会失败.
有没有其他方法来传递参数?
最佳答案 你可以为My_class实现一个__init__方法,它接受你想要提供的两个参数:
import multiprocessing as mp
import time
class My_class(mp.Process):
def __init__(self, name, num):
super(My_class, self).__init__()
self.name = name
self.num = num
def run(self):
print self.name, "created and waiting for", str(self.num), "seconds"
time.sleep(self.num)
print self.name, "exiting"
self.x()
def x(self):
print self.name, "X"
if __name__ == '__main__':
print 'main started'
p1=My_class('p1', 20)
p2=My_class('p2', 10)
p1.start()
p2.start()
print 'main exited'
您只需要确保在__init__方法中调用super(My_class,self).__ init __(),以便将您的类正确初始化为Process子类.