我有一个列表:
pokemonList = ['Ivysaur', 'Grass', 'Poison', '', 'Venusaur', 'Grass', 'Poison', '', 'Charmander', 'Fire', ''...]
请注意,模式是’口袋妖怪名称’,’它的类型’,”…下一个口袋妖怪
口袋妖怪有单一和双重形式.我如何对此进行编码,以便每个口袋妖怪(键)都将其各自的类型应用为其值?
到目前为止我得到了什么:
types = ("", "Grass", "Poison", "Fire", "Flying", "Water", "Bug","Dark","Fighting", "Normal","Ground","Ghost","Steel","Electric","Psychic","Ice","Dragon","Fairy")
pokeDict = {}
for pokemon in pokemonList:
if pokemon not in types:
#the item is a pokemon, append it as a key
else:
for types in pokemonList:
#add the type(s) as a value to the pokemon
正确的字典将如下所示:
{Ivysaur: ['Grass', 'Poison'], Venusaur['Grass','Poison'], Charmander:['Fire']}
最佳答案 只需迭代列表并适当地构造dict的项目.
current_poke = None
for item in pokemonList:
if not current_poke:
current_poke = (item, [])
elif item:
current_poke[1].append(item)
else:
name, types = current_poke
pokeDict[name] = types
current_poke = None