遍历包含python中的字符串和列表的元组列表

我有一个元组列表,其中包含一个字符串和另一个列表.它如下:

board = [('10S', []), ('3H', []), ('6C', ['KS', '9C']), ('6H', []), ('7D', []), ('9S', ['AS', 'KS'])]

我想遍历这样的比较,如下所示:

10S 3H
3H 6C
6C KS
6C 9C
6C 6H
6H 7D  

等等…

也就是说,下面写的get_mapping()将调用prev2和prev1的值.

我已经实现了以下代码:

for val in board:
    print "Val is: " + str(val)
    if cnt == 0:
        prev2 = val[0][0]
        prev1 = val[1][0]
        cnt += 1
        get_mapping(prev2,prev1,True)
    else:
        prev2 = prev1
        if len(val[1]) > 0:
            for v in val[1]:
                prev1 = v
                cnt += 1
                get_mapping(prev2,prev1,False)
        else:
            prev1 = val[0]
            cnt += 1
            get_mapping(prev2,prev1,True)    

我知道第一个条件是错误的.关于如何遍历以进行比较,我有点困惑.任何帮助将不胜感激.

最佳答案 你可以编写一个生成对的生成器:

from itertools import zip_longest

master_board_state = [('10S', []), ('3H', []), ('6C', ['KS', '9C']),
                      ('6H', []), ('7D', []), ('9S', ['AS', 'KS'])]

def pairs(state):
    for (key, lst), nxt in zip_longest(state, state[1:]):
        yield from ((key, x) for x in lst)
        if nxt is not None:
            yield key, nxt[0]

print('\n'.join(str(p) for p in pairs(master_board_state)))

输出:

('10S', '3H')
('3H', '6C')
('6C', 'KS')
('6C', '9C')
('6C', '6H')
('6H', '7D')
('7D', '9S')
('9S', 'AS')
('9S', 'KS')

zip_longest以上将从州生产物品.由于第一个参数在最后一次迭代时长于第二个参数,因此无用作fillvalue.然后循环将首先从返回(key,list item)元组的生成器产生,最后产生当前和下一个键.

更新对于Python 2,需要进行微小的修改,因为它没有产生的收益,而zip_longest被称为izip_longest

from itertools import izip_longest

master_board_state = [('10S', []), ('3H', []), ('6C', ['KS', '9C']),
                      ('6H', []), ('7D', []), ('9S', ['AS', 'KS'])]

def pairs(state):
    for (key, lst), nxt in izip_longest(state, state[1:]):
        for x in lst:
            yield key, x
        if nxt is not None:
            yield key, nxt[0]

print '\n'.join(str(p) for p in pairs(master_board_state))
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