python – 在Tensorflow Object Detection API中打印类名和分数

2019年8月3日 189次阅读

我正在使用Tensorflow对象检测API一切正常但我想打印一个dict或数组,其格式如下{Object name,Score}或类似的东西,我需要的是对象名称和分数.

我尝试使用以下代码：

with detection_graph.as_default():
  with tf.Session(graph=detection_graph) as sess:
    # Definite input and output Tensors for detection_graph
    image_tensor = detection_graph.get_tensor_by_name('image_tensor:0')
    # Each box represents a part of the image where a particular object was detected.
    detection_boxes = detection_graph.get_tensor_by_name('detection_boxes:0')
    # Each score represent how level of confidence for each of the objects.
    # Score is shown on the result image, together with the class label.
    detection_scores = detection_graph.get_tensor_by_name('detection_scores:0')
    detection_classes = detection_graph.get_tensor_by_name('detection_classes:0')
    num_detections = detection_graph.get_tensor_by_name('num_detections:0')
    for image_path in TEST_IMAGE_PATHS:
      image = Image.open(image_path)
      # the array based representation of the image will be used later in order to prepare the
      # result image with boxes and labels on it.
      image_np = load_image_into_numpy_array(image)
      # Expand dimensions since the model expects images to have shape: [1, None, None, 3]
      image_np_expanded = np.expand_dims(image_np, axis=0)
      # Actual detection.
      (boxes, scores, classes, num) = sess.run(
          [detection_boxes, detection_scores, detection_classes, num_detections],
          feed_dict={image_tensor: image_np_expanded})
      print ([category_index.get(value) for index,value in enumerate(classes[0]) if scores[0,index] > 0.5])

      threshold = 0.5 # in order to get higher percentages you need to lower this number; usually at 0.01 you get 100% predicted objects
      print(len(np.where(scores[0] > threshold)[0])/num_detections[0])

这部分是有效的

  print ([category_index.get(value) for index,value in enumerate(classes[0]) if scores[0,index] > 0.5])

它正在打印[{‘name’：’computer’,’id’：1}]他们是否能以任何方式将该对象的分数添加到字典？

我在他们使用的Stackoverflow上看到了另一个问题：

 threshold = 0.5 # in order to get higher percentages you need to lower this number; usually at 0.01 you get 100% predicted objects
 print(len(np.where(scores[0] > threshold)[0])/num_detections[0])

这给了我Tensor(“truediv：0”,dtype = float32)但是如果它工作的话虽然它还不够,因为我没有对象的名字.

谢谢

最佳答案 所以这是适合我的解决方案. (如果您仍在寻找解决方案,那就是)

# The following code replaces the 'print ([category_index...' statement
objects = []
for index, value in enumerate(classes[0]):
  object_dict = {}
  if scores[0, index] > threshold:
    object_dict[(category_index.get(value)).get('name').encode('utf8')] = \
                        scores[0, index]
    objects.append(object_dict)
print objects
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