SQL进阶教程 1-2-1 自连接的用法之排列组合

可重排列、排列、组合

此系列为Mick的SQL进阶教程的笔记,有错误的地方欢迎批评指正

这一部分,我们所用的数据库(表名:Products)如下:

name   price

香蕉     80

橘子     100

苹果      50

1.可重排列(可重的有序对即把所有排列的可能结果都显示)

代码:

SELECT P1.name AS name_1, P2.name AS name_2

FROM Products AS P1 CROSS JOIN Products AS P2

结果:

name_1 name_2

“苹果”    “苹果”

“苹果”    “橘子”

“苹果”    “香蕉”

“橘子”    “苹果”

“橘子”    “橘子”

“橘子”   “香蕉”

“香蕉”   “苹果”

“香蕉”   “橘子”

“香蕉”   “香蕉”

2.不可重排列(去重的有序对)

加一条筛选条件,把name_1=name_2的去除,只留下name_1不等于name_2的部分,即把1结果中斜体的部分去掉

代码:

SELECT P1.name AS name_1, P2.name AS name_2

FROM Products AS P1 CROSS JOIN Products AS P2

WHERE P1.name<>P2.name;

结果:

name_1 name_2

“苹果”    “橘子”

“苹果”    “香蕉”

“橘子”    “苹果”

“橘子”    “香蕉”

“香蕉”    “苹果”

“香蕉”    “橘子”

3.组合(无序对)

更改筛选条件,使得”苹果”    “橘子”/ “橘子”    “苹果”这样的排列只留下一个

代码:

SELECT P1.name AS name_1, P2.name AS name_2

FROM Products AS P1 CROSS JOIN Products AS P2

WHERE P1.name>P2.name; –这边>或者<都可以,这边我不太明白>和<的字符串是怎么计算的

>的结果:

name_1 name_2

“苹果”    “橘子”

“香蕉”   “苹果”

“香蕉”   “橘子”

<的结果:

name_1 name_2

“苹果”    “香蕉”

“橘子”    “苹果”

“橘子”    “香蕉”

练习题

1.请使用表Products,求出两列可重组合,结果应如下:

《SQL进阶教程 1-2-1 自连接的用法之排列组合》

2.请使用表Products,求出如下结果:

《SQL进阶教程 1-2-1 自连接的用法之排列组合》

练习题答案

1.

SELECT P1.name AS name_1, P2.name AS name_2

FROM Products AS P1 CROSS JOIN Products AS P2

WHERE P1.name>=P2.name

ORDER BY P1.name DESC;

2.

SELECT P1.name AS name_1, P2.name AS name_2,P3.name AS name_3

FROM Products AS P1 CROSS JOIN Products AS P2 CROSS JOIN Products AS P3

WHERE P1.name>P2.name AND P2.name>P3.name;

    原文作者:吃土少女欣
    原文地址: https://www.jianshu.com/p/909c39a83d68
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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