在经典的汉诺塔问题中,有 3 个塔和 N 个可用来堆砌成塔的不同大小的盘子。要求盘子必须按照从小到大的顺序从上往下堆 (如,任意一个盘子,其必须堆在比它大的盘子上面)。同时,你必须满足以下限制条件:
(1) 每次只能移动一个盘子。
(2) 每个盘子从堆的顶部被移动后,只能置放于下一个堆中。
(3) 每个盘子只能放在比它大的盘子上面。
请写一段程序,实现将第一个堆的盘子移动到最后一个堆中。
思路:
我们假设函数hanoi(n, a, b, c)用于将n个圆盘由a移动到c,b作为辅助柱子。
if n!=0 then ;预定值
hanoi(n-1, a, c, b) ;将n-1个盘子由a移动到b,以c为辅助柱子(注意参数顺序)
move(n,a,c) ;将a上的最后一个盘子移动到c
hanoi(n-1, b, a, c) ;将n-1个盘子由b移动到c,以a为辅助柱子
endif ;完成
.hpp
#ifndef C227_H
#define C227_H
#include<iostream>
#include<stack>
using namespace std;
class Tower {
private:
stack<int> disks;
public:
/* * @param i: An integer from 0 to 2 */
Tower(int i) {
// create three towers
}
/* * @param d: An integer * @return: nothing */
void add(int d) {
// Add a disk into this tower
if (!disks.empty() && disks.top() <= d) {
printf("Error placing disk %d", d);
}
else {
disks.push(d);
}
}
/* * @param t: a tower * @return: nothing */
void moveTopTo(Tower &t) {
// Move the top disk of this tower to the top of t.
t.add(disks.top());
disks.pop();
}
/* * @param n: An integer * @param destination: a tower * @param buffer: a tower * @return: nothing */
void moveDisks(int n, Tower &destination, Tower &buffer) {
// Move n Disks from this tower to destination by buffer tower
if (n <= 0)
return;
else if (n == 1)
moveTopTo(destination);
else{
moveDisks(n - 1, buffer, destination);
moveTopTo(destination);
buffer.moveDisks(n - 1, destination,*this);
}
}
/* * @return: Disks */
stack<int> getDisks() {
// write your code here
return disks;
}
};
#endif
/** * Your Tower object will be instantiated and called as such : *vector<Tower> towers; *for (int i = 0; i < 3; i++) towers.push_back(Tower(i)); *for (int i = n - 1; i >= 0; i--) towers[0].add(i); *towers[0].moveDisks(n, towers[2], towers[1]); *print towers[0], towers[1], towers[2] */
.cpp
#include"c227.h"
#include<vector>
void print(Tower t)
{
stack<int> sk = t.getDisks();
while (!sk.empty())
{
cout << sk.top() << " ";
sk.pop();
}
cout << endl;
}
int main()
{
int n = 5;
vector<Tower> towers;
for (int i = 0; i < 3; ++i)
towers.push_back(Tower(i));
for (int i = n-1; i >= 0; --i)
towers[0].add(i);
towers[0].moveDisks(n, towers[2], towers[1]);
cout << "towers[0]: " << endl;
print(towers[0]);
cout << "towers[1]: " << endl;
print(towers[1]);
cout << "towers[2]: " << endl;
print(towers[2]);
return 0;
}