我有这个数据库与表’crigsStaffActivity’.我设法检索值并显示它.但结果并没有表现出我的期望.
用值创建表的脚本
CREATE TABLE [dbo].[crigsStaffActivity]
(
[projectRef] [varchar](200) NOT NULL,
[activityLine] [int] NOT NULL,
[cost] [real] NOT NULL,
[staffCost] [varchar](500) NOT NULL
) ON [PRIMARY]
GO
INSERT [dbo].[crigsStaffActivity] ([projectRef], [activityLine], [cost], [staffCost])
VALUES (N'MRC/CRIGS/330', 1, 1, N'ProjectLeader'),
(N'MRC/CRIGS/330', 2, 2, N'Research Collaborators'),
(N'MRC/CRIGS/330', 1, 1, N'Project Collaborators'),
(N'MRC/CRIGS/330', 2, 2, N'Project Collaborators'),
(N'MRC/CRIGS/330', 2, 3, N'Research/Project Assistant');
ALTER TABLE [dbo].[crigsStaffActivity]
ADD CONSTRAINT [DF__crigsStaff__cost__5535A963] DEFAULT ((0)) FOR [cost]
GO
表格截图:
我的存储过程:
ALTER PROCEDURE [dbo].[getCrigsStaffActivity]
@ProjectRef AS VARCHAR(1000),
@staffCost AS varchar(1000)
AS
BEGIN
SET NOCOUNT ON;
DECLARE @val AS VARCHAR(2000);
SET @val='';
DECLARE @temp AS VARCHAR(2000);
DECLARE @activityLine AS VARCHAR(2000);
DECLARE @cost AS VARCHAR(2000);
DECLARE @ref as CURSOR;
SET @ref = CURSOR FOR
SELECT activityLine, cost
FROM crigsStaffActivity
WHERE projectRef = @ProjectRef
AND staffCost = @staffCost
OPEN @ref;
FETCH NEXT FROM @ref INTO @activityLine, @cost;
WHILE @@FETCH_STATUS = 0
BEGIN
FETCH NEXT FROM @ref INTO @activityLine, @cost;
SET @val = CONCAT(@activityLine,',',@cost);
END
CLOSE @ref;
DEALLOCATE @ref;
SELECT @val AS ref;
END
当我执行存储过程时,我得到这个结果:
ref
----
2,2
问题是,对于项目协作者,我有两个重复值,因此我需要得到这样的结果:
ref
-----
1,1
2,2
我的问题是如何实现上述结果.
这个存储过程的更好结果可能是:
ref
-----------------------------
1,1,ProjectLeader
2,2,Research collaborators
1,1,Project collaborators
2,2,Project collaborators
2,3,Research/Project Assistant
最佳答案 如果我弄错了.你不需要使用光标.
ALTER PROCEDURE [dbo].[getCrigsStaffActivity]
@ProjectRef AS VARCHAR(1000),
@staffCost AS varchar(1000)
AS
BEGIN
SET NOCOUNT ON;
SELECT CONCAT(activityLine,',', cost,',', staffCost) as ref
FROM crigsStaffActivity
WHERE projectRef = @ProjectRef
AND staffCost = @staffCost
END